|Basic Shear Wall Diagram|
|This second example is for a wall with higher shear
begins to overtake the weight of the system.
|Note that as lateral loads increase, the maximum tension
compression in the triangular force pair increases.
At the bottom diagram, adding the two resulting forces
For lateral loads (triangular force pair)...
Mot = (Vroof * H) + (Vwall * H/2)
For vertical loads (rectangular force)...
Mr = (Total Weight * L/2)
"a" = (Mr-Mot)/(Total Weight)
max. comp. = (2/3)*(Total Weight/a)
|The bottom diagram can be redrawn to show a single
force in place
of the triangular distribution. This is the first step in understanding the
use of hold-downs in shear walls.